I tired my best on this one...
4.(6y^2+4y-3)+ (3y^2+2)=
My WOrk=18y^4+12y-6
Unfortunately, your work is incorrect. Based on the original problem, it looks like you multiplied things together. The parentheses don't matter in this problem. Simply combine 6y^2 and 3y^2 to make 9y^2. Because there is only one monomial with just one y, you leave +4y alone. You then combine -3 and +2 to make -1. The answer is 9y^2+4y-1.
To solve this problem correctly, you need to combine the like terms within the parentheses and then combine them with the terms outside the parentheses.
Starting with the terms inside the parentheses:
(6y^2 + 4y - 3) + (3y^2 + 2)
You need to add the coefficients of the terms with the same exponent, in this case, y^2 and y:
6y^2 + 3y^2 = 9y^2
4y + 0y = 4y
-3 + 2 = -1
Now you can put the simplified terms together:
9y^2 + 4y - 1
So, the correct answer is 9y^2 + 4y - 1.