Can somebody please help me with this problem?

This is the index-„³ 5 6^-5


The radical sign did not show, but the problem is:
5 is the index (outside the radical sign and then 6 is squared to the -5th power (inside the radical sign is under the radical sign)

when adding and subtracting radical expressions does the doubled number go in the inner or outter of the radical

sign?

The doubled number would go inside the radical sign.

To determine where the number goes when adding or subtracting radical expressions, it depends on the structure of the expression.

If you have a radical expression like √x + √y or √x - √y, where both x and y are under the square root, you cannot combine them directly because they have different terms inside the radical. In this case, both numbers stay inside the radical, and you cannot simplify further.

If you have a radical expression like √x + √x or √y - √y, where the terms inside the radical are the same, then they can be combined. In this situation, you can simplify the expression by adding or subtracting the coefficients in front of the radical. For example, √x + √x simplifies to 2√x, while √y - √y simplifies to 0.

It's important to note that when combining radical expressions, you can only combine like terms. Terms with different values inside the radical cannot be simplified together.

When adding or subtracting radical expressions, you first need to simplify each radical expression separately. Then, if the index (or root) of the radicals are the same, you can combine like radicals by adding or subtracting their coefficients. The doubled number would go in the inner part of the radical, which means it would be added or subtracted from the number inside the radical sign.