what is the concentration of hydrogen ion in a 0.1M solution of sodium hydroxide(NaOH)?
NaOH dissolves and completely dissociates in H2O to form the ions.
NaOH ==> Na^+ + OH^-
Therefore, starting with 0.1 M NaOH will give you 0.1 M in Na^+ and 0.1 M in OH^-.
You know Kw=(H^+)(OH^-)
Kw is 1 x 10^-14.
(OH^-) = 0.1 M.
Solve for (H^+).
thank u so much for ur help DrBob222!
To calculate the concentration of hydrogen ions (H+) in a 0.1 M solution of sodium hydroxide (NaOH), you can use the equation Kw = (H+)(OH-), where Kw is the ion product constant for water.
In this case, you know that the hydroxide ion (OH-) concentration is 0.1 M because NaOH dissociates completely in water to form Na+ and OH-. Therefore, you can substitute 0.1 M for (OH-) in the equation.
Kw = (H+)(OH-)
1 x 10^-14 = (H+)(0.1)
Now, solve for (H+):
(H+) = (1 x 10^-14) / 0.1
(H+) = 1 x 10^-13 M
So, the concentration of hydrogen ions in a 0.1 M solution of sodium hydroxide is 1 x 10^-13 M.