A block of mass 3 kg initially at rest is pulled along a friction less horizontal surface with a force of 4N. The speed of the block at t=2s is
a)4/3 m/s
b)8/3m/s
c)4 m/s
d)8m/s
e)24m/s
For this problem this is a graph. Some of the points on the graph are (0,0),(1,2),(2,4),(3,6) where the x's is the time and the y's is the Force. I know that v=d/t but they don't give us time. Please help me.
The acceleration is a = F/m = 4/3 m/s^2
The velocity after 2 s is (1/2)at^2 =
(1/2)(4/3)(4) = ?
The answer is one of the multiple choices.
The answer is c) 4 m/s.
To solve this problem, we can use the equation v = u + at, where v is the final velocity, u is the initial velocity (which is 0 in this case), a is the acceleration, and t is the time. In this case, the initial velocity is 0 because the block is initially at rest.
We have already calculated the acceleration to be 4/3 m/s^2. Now we need to find the time, t = 2s.
Plugging these values into the equation, we get:
v = 0 + (4/3)(2)
v = 8/3 m/s
So the speed of the block at t = 2s is 8/3 m/s.
Therefore, the correct answer is b) 8/3 m/s.