Posted by **DANIELLE** on Thursday, December 21, 2006 at 10:20am.

When the digits of two-digits numbers are reversed, the new number is 9 more than the original number, and the sum of the digits of the original number is 11. What is the original number.

Can some one please help me here?

The tens digit is T, the units digit is U.

The number is TU, its value is 10T +U

Reverse it, subtract the origial number

10U + T - 10T -U =9

T+ U=11

Those are the guiding equations. Simplify the first, and solve.

## Answer this Question

## Related Questions

- Algebra 2 - The sum of the digits of a two-digit number is 9. If the digits are ...
- algebra - The sum of the digits of a two-digit number is eleven. If the digits ...
- math - the sum of the digits of a two digit number is 9. if the digits are ...
- algebra - The value of a certain two-digit number is eight times he sum of its ...
- math - The sum of the digits of a two-digit number is 16. If the digits are ...
- Algebra 1 - Hello, can someone check my answer the the question below? When the ...
- algebra - The digits of a two-digit number sum to 8. When the digits are ...
- math - The sum of the digits of a two-digit number is 14. If the numbers are ...
- algebra - A number consists of two digits. The sum of twice the tens digit an 5 ...
- Modeling with Linear Systems - The digits of a two-digit number sum to 8. When ...

More Related Questions