# maths

posted by
**sydney** on
.

how do i change x^2-4x-32=0 into (x+4)(x-8)=0

x^2-4x-32=0

=> x^2-8x+4x-32=0

=> x(x-8)+4(x-8)=0

=> (x-8)(x+4)=0

OR (x+4)(x-8)=0

X^{2} -4x -32 = 0

JUst factor it. It factors into

(X-8)(X+4)=0