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July 28, 2014

Homework Help: RATE, DISTANCE, TIME

Posted by CINDY on Thursday, December 21, 2006 at 2:16am.

TIM PADDLED HIS KAYAK 12 KM UPSTREAM AGAINST A 3 KM/H CURRENT AND BACK AGAIN IN 5 HR 20 MINUTES. iN THAT TIME
HOW FAR COULD HE HAVE PADDLED IN STILL WATER


12/(v+3) + 12/(v-3) = 5.33 hours

Solve for this speed in still water, v.

12(v-3) + 12(v+3) = 5.33 (v^2 -9)
24 v = 5.33 v^2 - 48
Use the quadratic equation and take the positive root for v.
v = 6.0 km/h

In the same time, the distance he could travel in still water is
D = 5.33 * v = 32 km

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