Sunday
April 20, 2014

Homework Help: RATE, DISTANCE, TIME

Posted by CINDY on Thursday, December 21, 2006 at 2:16am.

TIM PADDLED HIS KAYAK 12 KM UPSTREAM AGAINST A 3 KM/H CURRENT AND BACK AGAIN IN 5 HR 20 MINUTES. iN THAT TIME
HOW FAR COULD HE HAVE PADDLED IN STILL WATER


12/(v+3) + 12/(v-3) = 5.33 hours

Solve for this speed in still water, v.

12(v-3) + 12(v+3) = 5.33 (v^2 -9)
24 v = 5.33 v^2 - 48
Use the quadratic equation and take the positive root for v.
v = 6.0 km/h

In the same time, the distance he could travel in still water is
D = 5.33 * v = 32 km

Answer this Question

First Name:
School Subject:
Answer:

Related Questions

Algebra 2 - Tim paddled his kayak 12km upstream against a 3km/h current and back...
MATH!!!!!!! - The river boat paddled upstream at 12km/h, stopped for 2 h of ...
algebra - A canoeist can paddle 12 km upstream and 12 km back downstream in the ...
science - How do I predict how long will it take for lava to reach the town, ...
math - it took cindy 2h to bike from abbott to benson at a constant speed. the ...
physical science - Brad rides his bike 20 km. He covers the distance in 45 ...
Math - Steve can kayak at 8 km/h in still water. On the river, Steve and the ...
math - a boat travels 4 km upstream and 4 km back. the time for the round trip ...
math - donna took 3hours to row 18 km upstream. her return trip took 1 hour less...
algebra 2 - With the wind, a jet can fly 2500 km in 2 hours and 30 minutes. ...

Search
Members