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August 1, 2014

August 1, 2014

Posted by **Megan** on Wednesday, December 20, 2006 at 10:33pm.

I'm rather new at this but wouldn't b=2*sqrt(3) give (x+sqrt3)

Check my thinking.

for a quadratic equation to have exactly one root, the discriminat must be zero i.e

if equation is:

ax^2+bx+c=0 , then for exactly one root,

b^2-4ac=0

i.e.

b^2=4ac

for your equation,

x^2+bx+3=0

b^2=4(1)(3)

=12

hence

b=sqrt(12)

=2(sqrt(3))

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