Friday
August 1, 2014

Homework Help: Algebra

Posted by cbarnett on Tuesday, December 19, 2006 at 11:27am.

Here's the question: Jose needs to enclose a rectangular section of his yard. The area is 35 sq. ft. and the perimeter is 27 sq.ft. Find the length and width of the section.
The issue I'm having is that I think I need to find the common fators of 35 and 27 and they have no common factors so I have no idea what the answer is. Can anyone help?

L*W=35
2L + 2W= 27

From the first, L= 35/W put that in the second.

2*35/W + 2W= 27

multipy thru by W, and put in quadratic form, and use the quadratic equation or factor.

Answer this Question

First Name:
School Subject:
Answer:

Related Questions

Algebra 2( it's a tough one!) - Jose needs to enclose a rectangular section of ...
Math - The first question is this: Helen designs a rectangle with an area of 225...
Algebra 2 - ~Solving inequalities~ Hello everybody :-) I'm pretty good at ...
Algebra - John wants to build a corral next to his barn. He has 300 feet of ...
algebra II-URGENT - the perimeter of a rectangular yard is 270 feet. If its ...
Algebra II - The perimeter of a rectangular yard is 270 feet. If its length is ...
basic geometry - A rectangle has width the same asa a side of a square whose ...
college algebra word problem - Here's the problem I was asked: You are visiting ...
College Algebra - A rancher wishes to enclose a rectangular partitioned corral ...
Math - John wants to build a corral next to his barn.He has 300 feet of fencing ...

Search
Members