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March 31, 2015

March 31, 2015

Posted by **Alex** on Monday, December 18, 2006 at 4:42pm.

[integration sign] 4j-5j^3 dj

I got 2j^2 - 5/4j^4... is this my final answer?

If j is the variable, for the indefinite integral you have to add a constant. For the definite integral, you have to put in the lower, upper limits.

j is an unusual variable symbol, I am use to j being sqrt -1

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