# MATH, ALGEBRA

posted by
**jasmine20** on
.

cAN SOMEONE JUST SHOW ME HOW TO GET THE EQUATION IN ORDER TO SOLVE IT MYSELF. i'LL APPRECIATED.

bUSINESS AND FINANCE. The Randolphs used 12 more gal of fuel oil in October than in September and twice as much oil in November as in September. If they used 132gal for the 3months , how much was used during each month?

Let x = the gallons of fuel they used in Sept. So, 12 + x is gallons used in Oct, and 2x is gallons used in November. Then just add them all!!

Let O = gallons used in Oct.

let S = gallons used in Sept.

let N = gallons used in Nov.

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They used 12 more gallong of fuel oil in Oct than Sept; therefore, if we add 12 to Sept we will have the use in Oct.

O = S+12

They used twice as much oil in Nov as in Sept; therefore, if we multiply the use in Sept by 2 we will get Nov use.

N = 2S

The total is 132 gallongs.

N + O + S = 32.

Three equations. Three unknowns.

**Hint: Take the total equation (the last one) and substitute values for O and N and solve for S. I think S should be 30 gallons. Check my thinking. Check my work.
Obviously, I didn't hit the 1 for the last equation. It should be
N + O + S = 132
My fingers aren't as nimble as they were at one time.
how did you get the gallons for each month? to come out right**