Posted by Min on .
174520 = (massboiled) (2260)
.1716 = massboiled
Suppose a burner transfers 325 kJ of energy to 450 kg of liquid water at 20 C degrees. What mass of the water would be boiled away?
The first energy going in heats the water:
energy=mass*c*(100-20) Then subtract that from the intial 325kJ.
Then, you can figure the mass of water boiled away:
heatleft=massboiled*Lv Where Lv is the heat of vaporization.