Paul was able to jump rope 35 more times than Daniella. If Paul jumped 123 times, how many times did Daniella jump rope?
My sol: Let x = # times Daniella jump rope. Then Paul is: x+35
Sol: (x+35)+ x = 123 (?)
It doesn't seem quite right. I love math, but sometimes don't grasp the concepts of the problems. Please help me with a thought pattern on this one.
It seems too simple
123-35=x
x=88
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Find the interquartile range (IQR) of the data
98 132 295 68 176 89 287 198 94 68 240 94 369 94 155
To solve this problem, let's break it down step-by-step:
1. Let x represent the number of times Daniella jumped rope.
2. According to the problem, Paul jumped 35 more times than Daniella. So Paul's number of jumps can be represented as x + 35.
3. We are given that Paul jumped 123 times. So the equation becomes: x + 35 = 123.
4. Now we need to solve for x. To do that, we need to isolate x by subtracting 35 from both sides of the equation.
x + 35 - 35 = 123 - 35
x = 88
Therefore, Daniella jumped rope 88 times.