Tuesday

March 31, 2015

March 31, 2015

Posted by **Jen** on Wednesday, December 13, 2006 at 9:42pm.

Thanks.

If those are absolute value signs, the derivative will not exist when sin (pi/x) = 0, because of the sign change that occurs there. Assume sin (pi/x) > 0

Let u(x) = pi/x and v(x) = sin x, and use the chain rule.

d/dx ln v(u(x))=

d/dv dv/du du/dx

= -[1/(sin (pi/x])*cos x*(pi/x^2)

That assumes sin (pi/x) is positive. Change the sign if it is negative

**Answer this Question**

**Related Questions**

Calculus - Consider the function f(x)=sin(1/x) Find a sequence of x-values that ...

Calculus - Consider the function f(x)=sin(1/x) Find a sequence of x-values that ...

Calculus - Consider the function f(x)=sin(1/x) Find a sequence of x-values that ...

Calculus - Evaluate the integral. S= integral sign I= absolute value S ((cos x...

Calculus 12th grade (double check my work please) - 1.)Find dy/dx when y= Ln (...

tigonometry - expres the following as sums and differences of sines or cosines ...

Calculus - Consider the function f(x)=sin(1/x) Find a sequence of x-values that ...

TRIG! - Posted by hayden on Monday, February 23, 2009 at 4:05pm. sin^6 x + cos^6...

calculus - Could someone check my reasoning? thanx Find the derivative of the ...

algebra - Can someone please help me do this problem? That would be great! ...