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December 20, 2014

December 20, 2014

Posted by **Anne** on Tuesday, December 12, 2006 at 10:05pm.

Arg

1. P-->Q

2. ~P ^:~Q

Arg

If Peter is perceptive, then Quincy is a quack. Quincy, however, is not a quack. So Peter's not perceptive. (Hint: this is a valid argument)

This logical argument is valid under the following condition.

If and only if Peter is perceptive, then Quincy is a quack. Quincy, however, is not a quack. So Peter's not perceptive.

Truth table

PP QQ

T T

F F

I have no idea what you mean by group I rules.

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