Posted by **NICOLE** on Tuesday, December 12, 2006 at 2:44pm.

HOW DO YOU FIND THE VELOCITY OF A 20 kg SOLID CYLINDER WITH A .25 m RADIUS WHEN IT IS RELEASED FROM THE TOP OF A 10 m LONG RAMP INCLINED AT 30 DEGREES?

The potential energy at the top is mg10/sin30

The Ke at the bottom is 1/2 mv^2, plus 1/2 Iw^2

but w= v/r

so KE = 1/2 mv^2 + 1/2 I v^2/r^2

set that equal to PE, and solve for V.

YOu have to lookup or determine the moment of inertia for a solid cylinder.