Monday

March 30, 2015

March 30, 2015

Posted by **NICOLE** on Tuesday, December 12, 2006 at 2:44pm.

The potential energy at the top is mg10/sin30

The Ke at the bottom is 1/2 mv^2, plus 1/2 Iw^2

but w= v/r

so KE = 1/2 mv^2 + 1/2 I v^2/r^2

set that equal to PE, and solve for V.

YOu have to lookup or determine the moment of inertia for a solid cylinder.

**Answer this Question**

**Related Questions**

PHYSICS - A 20.0 kg solid cylinder, 0.25m in radius, and a 5.0 kg thin hollow ...

PHYSICS 2 - A 2.0 kg cylinder (radius = 0.08 m, length = 0.50 m) is released ...

physics help 3 please!! - A 2.0 kg cylinder (radius = 0.08 m, length = 0.50 m) ...

Physics Help.. - A small cube (m=0.290 kg) is at a height of 261 cm up a ...

Physics please help!! - A 1.94 kg solid sphere (radius = 0.105 m) is released ...

physics - A student is skateboarding down a ramp that is 6.52 m long and ...

physics - A student is skateboarding down a ramp that is 6.88 m long and ...

Physics - A student is skateboarding down a ramp that is 5.38 m long and ...

Physics - Four objects - a hoop, a solid cylinder, a solid sphere, and a thin, ...

College Physic - I am stuck on this question. Any help will be greatly ...