Posted by **NICOLE** on Tuesday, December 12, 2006 at 2:44pm.

HOW DO YOU FIND THE VELOCITY OF A 20 kg SOLID CYLINDER WITH A .25 m RADIUS WHEN IT IS RELEASED FROM THE TOP OF A 10 m LONG RAMP INCLINED AT 30 DEGREES?

The potential energy at the top is mg10/sin30

The Ke at the bottom is 1/2 mv^2, plus 1/2 Iw^2

but w= v/r

so KE = 1/2 mv^2 + 1/2 I v^2/r^2

set that equal to PE, and solve for V.

YOu have to lookup or determine the moment of inertia for a solid cylinder.

## Answer this Question

## Related Questions

- PHYSICS - A 20.0 kg solid cylinder, 0.25m in radius, and a 5.0 kg thin hollow ...
- PHYSICS 2 - A 2.0 kg cylinder (radius = 0.08 m, length = 0.50 m) is released ...
- physics help 3 please!! - A 2.0 kg cylinder (radius = 0.08 m, length = 0.50 m) ...
- Physics please help!! - A 1.94 kg solid sphere (radius = 0.105 m) is released ...
- Physics Help.. - A small cube (m=0.290 kg) is at a height of 261 cm up a ...
- physics - A student is skateboarding down a ramp that is 6.52 m long and ...
- physics - A student is skateboarding down a ramp that is 6.88 m long and ...
- Physics - A student is skateboarding down a ramp that is 5.38 m long and ...
- Physics - Four objects - a hoop, a solid cylinder, a solid sphere, and a thin, ...
- College Physic - I am stuck on this question. Any help will be greatly ...