Well, bobpursley explained this to me. I didn't understand this well. Since there was an error in the data, I am posting it again
t(sec) v(ft/sec)
1 12.2
1.5 13
2 13.4
2.5 13.7
velocity of an object moving along a line at various times.
How do I estimate the object's acceleration(in ft/sec^2) at t=1
TIA
acceleration at t=1 estimate
delta V=13-12.2
De;ta T= .5
that is the deltas between t=1, and t=1.5
acceleration=deltaV/deltatime
To estimate the object's acceleration at t=1, you can follow these steps:
1. Identify the change in velocity (delta V) between t=1 and t=1.5. In this case, delta V is calculated by subtracting the velocity at t=1 (12.2 ft/sec) from the velocity at t=1.5 (13 ft/sec):
delta V = 13 ft/sec - 12.2 ft/sec = 0.8 ft/sec
2. Determine the change in time (delta t). In this case, delta t is the time difference between t=1 and t=1.5, which is 0.5 seconds.
3. Divide the change in velocity (delta V) by the change in time (delta t). This will give you the estimate of the object's acceleration at t=1, in ft/sec^2:
acceleration = delta V / delta t = 0.8 ft/sec / 0.5 sec = 1.6 ft/sec^2
Therefore, the estimated acceleration of the object at t=1 is 1.6 ft/sec^2.