Posted by **Desiree** on Monday, December 11, 2006 at 3:50pm.

Given 120mL of neon gas at 40 degrees C, what teperature corresponds to a volume that has been decreased by 30mL?

(P1V2)/T1 = (P2V2)/T2.

Use V1 = 120 mL and V2 = 120-30=90 mL

Don't forget to change degrees C to Kelvin.

Kelvin = 273 +

^{o}C.

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