# another physics question

posted by
**Jen** on
.

A liquid ( = 1.65 g/cm3) flows through two horizontal sections of tubing joined end to end. In the first section the cross-sectional area is 10.0 cm2, the flow speed is 275 cm/s, and the pressure is 1.20 105 Pa. In the second section the cross-sectional area is 3.50 cm2.

a.Calculate the smaller section's flow speed.

b.Calculate the smaller section's pressure.

I found part a but not b.

a. Use the equation of continuity A1V1=A2V2

b. Use bernoullis equation. If you post your work, perhaps we can help.