Posted by **Jasmine** on Saturday, December 9, 2006 at 6:08pm.

Please help with this one. I've worked it out in so many ways and can't tell what's correct.

sinA sinA

----- - ------

1+sinA 1-sinA

Which answer is correct for the problem above?

a) 1+cotA

b) sinA tanA

c) -2tan^2A

d) secA cscA

common denominator: 1-sin^2 A

and that is equal to cos^2 A.

Numerator:

sinA-sin^2A - sinA -sin^2 A

-2sin^2 A

The result:

-2sin^2A /cos^2 A and you recall that tan u= sinU/cosU

## Answer This Question

## Related Questions

- Maths - Hi, can someone give me the answer to this question: secA-tanA=1/4. Find...
- further mathematics - Let P=(cosA sinA) (sinA cosA) Q=(cosB sinA) (sinB cosA) ...
- Maths - Prove that [sinA/(1-cosA)-(1-cosA)/sinA]*[cosA/(1+sinA)+(1+sinA)/cosA]=...
- Math - In any angle ABC prove that the perimeter = a/Sin A(Sin A + Sin B + Sin C...
- Trigonometric Identities - Verify/prove the following: (sinA+tanA)/(1+secA) = ...
- Trig - IfA=340°, prove that 2cosA/2 = -(v1+sinA) - (v1-sinA)
- trig - Solve (1+tan square A)(1-sinA)(1+ sinA)
- Trig - Ambiguous Cases - Triangle HAV has <H = 124, a=8.5mm, and h=7.2mm How ...
- trig - Please help me how to do this: 1) 1 + sina*cosa / (cosa + sina)^2 = 2) ...
- trig - If (cosa-sina)/sina = 2 , then what is tga = ?

More Related Questions