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March 29, 2015

March 29, 2015

Posted by **Jen** on Saturday, December 9, 2006 at 1:14pm.

How is dA/dt related to da/dt, db/dt and dè/dt

dA/dt= 1/2 b SinTheta da/dt + 1/2 a SinTheta db/dt + 1/2 ab cosTheta dTheta/dt

This is a U = xyz form

dU/dt= xy dz/dt + ...

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