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October 24, 2014

October 24, 2014

Posted by **nick** on Thursday, December 7, 2006 at 5:48pm.

y^2=-4x and x^2=y

I set both equations equal to 0, but only get x=0 and there is another intercepting point. please help!

You can solve for one of the equation and substitute it into the other equation. In this case you already have y=x^2 so just plug x^2 into y in the other equation. Once you solve for X ((-4)^(1/3) you can solve for Y (-4)^(2/3)

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