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November 28, 2014

November 28, 2014

Posted by **nick** on Thursday, December 7, 2006 at 4:52pm.

y=12/12X-y^3 ????

Any idea anyone???

y=12/12X-y^3 I assume you mean...

y=12/(12X-y^3)

12Xy-y^4=12

12x dy/dx + 12y -4y^3 dy/dx=0

dy/dx (12x -4y^3)=-12y

solve for dy/dx

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