Question: Calculate the frequency of the AA, Aa, and aa genotypes after one generation if the initial population consists of 0.2 AA, 0.6 Aa, and 0.2 aa.

What I have done is:

P = (0.2)+(0.5)(0.6)= 0.50

q = 1-p = 1 - 0.50 = 0.50

Can someone check my answer plz.

To calculate the frequency of the AA, Aa, and aa genotypes after one generation, you need to use the Hardy-Weinberg principle.

The Hardy-Weinberg principle states that the frequencies of alleles in a population will remain constant from generation to generation in the absence of other factors such as mutation, selection, migration, and genetic drift.

To calculate the frequency of each genotype, you need to use the following equations:
- Frequency of AA genotype (p^2)
- Frequency of Aa genotype (2pq)
- Frequency of aa genotype (q^2)

In your calculation, you have correctly determined the values of p and q. However, the values you have assigned to the initial population (0.2, 0.6, and 0.2) do not represent the frequencies of the genotypes; they represent the proportions or proportions of individuals within the population.

To convert these proportions to frequencies, divide each proportion by the sample size. Assuming the sample size is 1, you would have the following frequencies for the initial population:
- Frequency of AA genotype (0.2 / 1)
- Frequency of Aa genotype (0.6 / 1)
- Frequency of aa genotype (0.2 / 1)

So, reevaluating your equations:
- Frequency of AA genotype (p^2) = (0.2 / 1)^2
- Frequency of Aa genotype (2pq) = 2 * (0.2 / 1) * (0.6 / 1)
- Frequency of aa genotype (q^2) = (0.2 / 1)^2

These calculations will give you the frequencies of each genotype after one generation.