posted by Tammy on .
if the incidence of cystic fibrosis is 1 in 2500, what is the expected frequency of carriers for the CF allels? assume that this population is in Hardy-Weinberg equilibrium.
I appreciate a hint to start this answering this problem.
p^2 + 2pq + q^2 = 1
p + q = 1
q^2 is the percentage of cystic fibrosis cases (cc) cases.
That is how you start it. Repost if you get stuck!