Posted by **Jay** on Wednesday, December 6, 2006 at 5:26pm.

find the integral

secxtanxdx

and

if dy/dx= 2x/y^2 and y(o) = 3 then what is y(1) equal to

and differentiate

2pi + 3secx

secxtanxdx =

Sin(x)/Cos^2(x)dx

The integral is 1/Cos(x) + c

dy/dx= 2x/y^2 and y(o) = 3 then what is y(1) equal to

y^2 dy = 2x dx --->

1/3 y^3 = x^2 + c

y(0) = 3 --->

c = 9

## Answer this Question

## Related Questions

- Integral - That's the same as the integral of sin^2 x dx. Use integration by ...
- Integration by Parts - integral from 0 to 2pi of isin(t)e^(it)dt. I know my ...
- Calculus help?? - I'm not sure how to solve this and help would be great! d/dx [...
- calc.- trig substitution - s- integral s 1/ [ (x^4) sq.rt(x^2+9)] i know x=3tanx...
- calc - d/dx integral from o to x of function cos(2*pi*x) du is first i do the ...
- Integral Help - I need to find the integral of (sin x)/ cos^3 x I let u= cos x, ...
- trig integration - s- integral endpoints are 0 and pi/2 i need to find the ...
- trig integration - i'm having trouble evaluating the integral at pi/2 and 0. i ...
- Calculus - Hello, I have some calculus homework that I can't seem to get started...
- Calculus - I have two questions, because I'm preparing for a math test on monday...

More Related Questions