# math

posted by
**Jay** on
.

find the integral

secxtanxdx

and

if dy/dx= 2x/y^2 and y(o) = 3 then what is y(1) equal to

and differentiate

2pi + 3secx

secxtanxdx =

Sin(x)/Cos^2(x)dx

The integral is 1/Cos(x) + c

dy/dx= 2x/y^2 and y(o) = 3 then what is y(1) equal to

y^2 dy = 2x dx --->

1/3 y^3 = x^2 + c

y(0) = 3 --->

c = 9