Sunday

April 20, 2014

April 20, 2014

Posted by **Jay** on Wednesday, December 6, 2006 at 5:26pm.

secxtanxdx

and

if dy/dx= 2x/y^2 and y(o) = 3 then what is y(1) equal to

and differentiate

2pi + 3secx

secxtanxdx =

Sin(x)/Cos^2(x)dx

The integral is 1/Cos(x) + c

dy/dx= 2x/y^2 and y(o) = 3 then what is y(1) equal to

y^2 dy = 2x dx --->

1/3 y^3 = x^2 + c

y(0) = 3 --->

c = 9

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