Thursday

September 18, 2014

September 18, 2014

Posted by **Jack** on Wednesday, December 6, 2006 at 12:35am.

x^5 = -1 = e^[i (2n + 1) pi]

where i is any integer

x = [e^[i (2n + 1) pi]]^(1/5)

= e^(i pi/5)= cos pi/5 + i sin (pi/5)

= e^(3 i pi/5)

= cos (2 pi/5) + i sin (2 pi/5)

etc.

**Answer this Question**

**Related Questions**

maths/ physics - Determine the two square roots of 3+j4 in both a)Cartesian form...

pre-calculus - find the cube roots of -216 answer in polar form

pre-calculus - find the cube roots of -216 answer in polar form and complex

Maths - Polar Coordinate Systems - I've recieved an assignment to investigate ...

Pre-calculus; urgent ! Please help ! - 1.Graph the polar equation r=3-2sin(theta...

calculus - for what value of r=4sinč have vertical tangent? In polar coordinates...

pre-algebra - find the product: (4k to the 5th power)(-2k)to the 3rd power. 5th ...

math - Express z = 1 + 2j in polar form then find z^3 then convert the answer to...

Pre Cal. - Express 5sqrt(3) - 5i in polar form. A: 10(cos(11pi/6) + i sin(11pi/6...

Pre-Algebra - Find each product or Quotient. Express using exponents. 1. The ...