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December 21, 2014

December 21, 2014

Posted by **Jack** on Wednesday, December 6, 2006 at 12:35am.

x^5 = -1 = e^[i (2n + 1) pi]

where i is any integer

x = [e^[i (2n + 1) pi]]^(1/5)

= e^(i pi/5)= cos pi/5 + i sin (pi/5)

= e^(3 i pi/5)

= cos (2 pi/5) + i sin (2 pi/5)

etc.

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