Tuesday

September 30, 2014

September 30, 2014

Posted by **Ronald** on Tuesday, December 5, 2006 at 12:50am.

Let V be the tank volume. Pipe A fills at (1/8 V) per hour and pipe B fills at (1/12) V per hour. Let t be the elapsed time after 1:30. At that time, the volume filled (x) is

x = (1.5 + t) * (1/8) V + t (1/12) V = V

0.1875 V + 0.125 V t + 0.0833 V t = V

0.1875 + 0.2083 t = 1

Solve for t, which will be in hours. I get 3.90, or 3 hours 54 minutes after 1:30, when Pipe B was turned on

Check my algebra; I don't guarantee it

**Answer this Question**

**Related Questions**

algebra 2 - Pipes A and B can fill a storage tank in 8 hours and 12 hours, ...

college algebra - an inlet pipe can fill a large water tank in 3 hours. an ...

college algebra - water from a tank is being used for irrigation while the tank ...

Math - A tank is filled with an intake pipe that will fill it in 5 hours and an ...

math - the fill pipe for a tank can fill the tank in 4 hours and the drain pipe ...

Algebra - Two pipes fill a storage tank in 9 hours. If the larger pipe fills the...

math - a tank can be filled by one pipe in 3.5 hours and emptied by another in 4...

Math - One pipe fills a tank in 1 hour while another pipe can fill the same tank...

math - A tank fitted with two pipes is to filled with water. One pipe can fill ...

maths - a tank can be filled by one pipe in 3.5 hours and emptied by another in ...