posted by drwls .
The indefinite integral, or which call the "antiderivative", of f'(x)=6x-8x^3
is f(x) = 3x^2 - 2x^4 + C
where C is any constant.
Plug in x = 2 to that to see what C is.
3 = 3*4 - 2*16 + C
Determine the antiderivative of the following function given the initial condition: f'(x)=6x-8x^3 given that
f(x)= 6x^2/2 - 8x^4/4 + C
Put in x=2 and solve for C