Friday

February 27, 2015

February 27, 2015

Posted by **AS** on Saturday, December 2, 2006 at 12:48pm.

60L x 1/2 (hour 1) = 30 L leaving 30L.

30L x 1/3 (hour 2) = 10 L leaving 20L.

20L x 1/4 (hour 3) = 5 L leaving 15L.

15L x 1/5 (hour 4) = 3 L leaving 12L.

12L x 1/6 (hour 5) = 2 L leaving 10L.

Note that the denominator of the fraction is 1 more than the time; therefore, t + 1.

60L x 1/(t+1) = 10 L

solve for t = 5 hours. Actually, you would need 1 second longer to have less than 10L. Check my thinking. Check my arithmetic.

3=60(30)^(x/1590)

3=60(30)^(x/1590)

**Answer this Question**

**Related Questions**

chemistry help please! - For my year 7 homework i have had to write a poster ...

algebra - Parking in a student cost $3 for the first half hour and $1.50 for ...

algebra - parking in a student lot cost $1 for the first half hour and $1.75 for...

Algebra - Parking in a student parking lot costs 2.00 for the first half hour ...

Algebra - Parking in a student lot cost $2 for the first half hour and $1.25 for...

Chemistry - Calculate the pressure in an evacuated 250. mL container at 0.00 ...

Math - Susan finished typing 1/9 of an article in the first houe and finished 1....

Algebra - Parking in a students lot cost $1 for the first half hour and $1.25 ...

Algebra - Parking in a student lot cost $1 for the first half hour and $1.25 for...

algebra word problem - A long distance runner starts at the beginning of a trail...