Sunday
April 19, 2015

Homework Help: chemistry

Posted by tyler on Wednesday, November 29, 2006 at 9:01pm.

The enthalpy of vaporization of benzene, C6H6(l), is 33.9 kJ mol?1 at 298 K. How many liters of C6H6(g), measured at 298 K and 88.7 mmHg, are formed when 1.90 kJ of heat is absorbed by C6H6(l) at a constant temperature of 298 K?


not sure what formulae to use, thanks!


M = Q/([heat of vaporization)
1.90 kJ/ 33.9 kJ/mol = 0.056 moles

Use the perfect gas law to covert that number of moles to liters of gas. Be sure to use the low pressure of 88.7 mm Hg

sweet dude got it

ihope thx

Answer this Question

First Name:
School Subject:
Answer:

Related Questions

General Chemistry - The enthalpy of vaporization of benzene liquid is 33.9 kJ/...
Chemistry - How much heat would be required to convert 234.3 g of solid benzene...
chemisty - The molar heat capacity of C6H6(ℓ) is 136 J/mol ◦C and ...
chemistry - 2.9 The standard enthalpy of formation of the metallocene bis(...
chemistry - The enthalpy of vaporization at 298 K for diethylether (C4H10C) is ...
chemistry - Benzene, C6H6, is a known carcinogen that burns in air according to ...
Chemistry - Suppose that 1.048 g of benzene is combusted in a bomb calorimeter ...
Chemistry - Carbon tetrachloride (CCl4) and benzene (C6H6) form ideal solutions...
Chemistry - Reposting with correct information..Carbon tetrachloride (CCl4) and ...
Chemistry - 27) What volume of benzene (C6H6, d= 0.88 g/mL, molar mass = 78.11 g...

Members