For two consecutive integers, the sum of the smaller and twice the larger is 38. What are the integers?
Plz explain. Thanks
2(a+b)=38
Therefore:
a+b+(2(a+b)=38
a+b+2a+2b=38
3a+3b=38
3(a+b)=38
I got as far a here. I don't know if this helps. My last stop may be worng. This might help?
r u kidding me?this is like the easiest math ever..38 divide by 2 is 19 so a+b equals 19..
r u kidding me?this is like the easiest math ever..38 divide by 2 is 19 so a+b equals 19..
r u kidding me?this is like the easiest math ever..38 divide by 2 is 19 so a+b equals 19..
I apologize if my previous explanation was unclear. Let me clarify further.
To solve this problem, let's break it down step by step:
Step 1: Translate the problem into an equation.
The problem states that the sum of the smaller integer, let's call it "a", and twice the larger integer, let's call it "b", is 38. So, we can write the equation as follows:
a + 2b = 38
Step 2: Express one variable in terms of the other variable.
We can isolate one variable by rearranging the equation. Let's solve for "a" in terms of "b":
a = 38 - 2b
Step 3: Find consecutive integers that satisfy the equation.
Consecutive integers are integers that follow each other in order without gaps. In this case, we are looking for two consecutive integers that satisfy the equation.
Let's substitute the expression for "a" from step 2 into the equation from step 1:
(38 - 2b) + 2b = 38
38 - 2b + 2b = 38
38 = 38
As you can see, this equation doesn't provide any specific values for "a" and "b". That's because the given problem is not solvable with the provided information. The equation leads to a contradiction, which means there is no solution that satisfies it.
Therefore, we cannot determine the two consecutive integers that satisfy the given conditions in this case, as there seems to be an error in the problem statement itself.