Posted by **Jamie** on Wednesday, November 29, 2006 at 6:11pm.

For two consecutive integers, the sum of the smaller and twice the larger is 38. What are the integers?

Plz explain. Thanks

2(a+b)=38

Therefore:

a+b+(2(a+b)=38

a+b+2a+2b=38

3a+3b=38

3(a+b)=38

I got as far a here. I don't know if this helps. My last stop may be worng. This might help?

r u kidding me?this is like the easiest math ever..38 divide by 2 is 19 so a+b equals 19..

r u kidding me?this is like the easiest math ever..38 divide by 2 is 19 so a+b equals 19..

r u kidding me?this is like the easiest math ever..38 divide by 2 is 19 so a+b equals 19..

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