Posted by **samantha** on Wednesday, November 29, 2006 at 1:54pm.

a rectangle is twice as long as it is wide. if both of its dimensions are increased by 4m, its area is increased by 88m^2 find the dimensions of the original rectangle

Original rectangle = w for width and 2w for length. Area = w x 2w

Larger rectangle = w+4 for width and 2w+4 for length. Area = (w+4)*(2w+4)

The problem states that the larger rectangle has an area that is 88 m

^{2} more than the original.

Put that in equation form.

area of rectangle 2 - area of rectangle 1 = 88.

(w+4)*(2w+4)-(w*2w)=88.

Solve for w. The length will be twice that. Post your work if you run into trouble.

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