Sunday
April 19, 2015

Homework Help: math

Posted by samantha on Wednesday, November 29, 2006 at 1:54pm.

a rectangle is twice as long as it is wide. if both of its dimensions are increased by 4m, its area is increased by 88m^2 find the dimensions of the original rectangle

Original rectangle = w for width and 2w for length. Area = w x 2w

Larger rectangle = w+4 for width and 2w+4 for length. Area = (w+4)*(2w+4)

The problem states that the larger rectangle has an area that is 88 m2 more than the original.
Put that in equation form.
area of rectangle 2 - area of rectangle 1 = 88.

(w+4)*(2w+4)-(w*2w)=88.

Solve for w. The length will be twice that. Post your work if you run into trouble.

Answer this Question

First Name:
School Subject:
Answer:

Related Questions

algebra - The sides of an rectangle was 5cm by 9cm. When both dimension were ...
trigonometry - the length of a rectangle is 2cm longer than the width. if its ...
trigonometry - the length of a rectangle is 2cm longer than the width. if its ...
Algebra - the length of a rectangle is 5m more than twice its width. and the ...
solving quadratic equations by factoring - the original dimensions of a ...
solving quadratic equations by factoring - the original dimensions of a ...
math - A rectangle is 4 times as long as it is wide. A 2nd rectangle is ...
MATH OMG HELP - The base and height of an original rectangle are each increased ...
alegbra1 - The length of a rectangle is twice the width. If the length is ...
Algebra - A rectangle was 25 cm longer than it was wide. A new rectangle was ...

Members