Monday

December 22, 2014

December 22, 2014

Posted by **samantha** on Wednesday, November 29, 2006 at 1:54pm.

Original rectangle = w for width and 2w for length. Area = w x 2w

Larger rectangle = w+4 for width and 2w+4 for length. Area = (w+4)*(2w+4)

The problem states that the larger rectangle has an area that is 88 m

Put that in equation form.

area of rectangle 2 - area of rectangle 1 = 88.

(w+4)*(2w+4)-(w*2w)=88.

Solve for w. The length will be twice that. Post your work if you run into trouble.

**Answer this Question**

**Related Questions**

algebra - The sides of an rectangle was 5cm by 9cm. When both dimension were ...

Algebra - the length of a rectangle is 5m more than twice its width. and the ...

math - A rectangle is 4 inches wide by 7 inches long. When the length and width ...

trigonometry - the length of a rectangle is 2cm longer than the width. if its ...

trigonometry - the length of a rectangle is 2cm longer than the width. if its ...

Math - If the width of a rectangle is increased by 2 inches, the area is 140 ...

math - The leng of the smaller rectangle is 1 inch less than twice its wide. ...

Geometry - A rectangualar playground is 4 meters longer than it is wide. If the ...

math help - ) Brian has 96 feet of fencing to enclose a rectangular space in his...

geometry - A rectangle is twice as long as it is wide. Its perimeter is48 cm. ...