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January 31, 2015

January 31, 2015

Posted by **Anonymous** on Wednesday, November 29, 2006 at 10:46am.

y-3

No, it is not y-3

[(y2-9)/4y] * 12/(3y+9)

=(1/4)(y+3)(y-3)(1/y)*(1/3)*[4/(y+3)]

=(y-3)/(3y)

thank you

but that wasn't an answer choice. (y-3)/y was an answer choice though

Sorry, I made an algebra error factoring the "12"

=(1/4)(y+3)(y-3)(1/y)*(1/3)*[3*4/(y+3)]

=(y-3)/y

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