Saturday

February 28, 2015

February 28, 2015

Posted by **ashish** on Wednesday, November 29, 2006 at 1:28am.

Write equations for the amount of both rolls of material needed to produce seven cans, as a function of the diameter of the can. The height can be expressed in terms of the required volume, V, and the diameter, D.

V = (1/4) pi D^2 h

h = 4 V/[pi D^2]

Then compute the total cost of the material and processing for seven cans, as a function of diameter only, with V as a constant.

Differentiate Cost vs(D) and set the derivative = 0. Then solve for the optimum diameter.

The reason you should do this for seven cans is that you get seven lids at a time, with minimum waste. Remember than seven cans require a total of 14 tops and bottoms

**Answer this Question**

**Related Questions**

Calculus - A right cicular cylindrical can is to be constructed to have a volume...

math - A right cicular cylindrical can is to be constructed to have a volume of ...

math - A right cicular cylindrical can is to be constructed to have a volume of ...

math - A cylindrical container has a volume of 226 cubic inches. the container ...

math - A cylindrical gasoline can is 18 inches across and 20 inches tall.which ...

math 2 - max packs cereal boxes into a larger box the volume of each cereal box ...

heat - 20 cubic inches of a gas with an absolute pressure of 5 psi is compressed...

Math - The length of a piece of cardboard is two inches more than its width. an ...

mathematics - A cylindrical gasoline can is 18 inches across and 20 inches tall...

Math - A cylindrical soup can has a radius of 4.1 inches and a height of 2 ...