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November 23, 2014

November 23, 2014

Posted by **ashish** on Wednesday, November 29, 2006 at 1:28am.

Write equations for the amount of both rolls of material needed to produce seven cans, as a function of the diameter of the can. The height can be expressed in terms of the required volume, V, and the diameter, D.

V = (1/4) pi D^2 h

h = 4 V/[pi D^2]

Then compute the total cost of the material and processing for seven cans, as a function of diameter only, with V as a constant.

Differentiate Cost vs(D) and set the derivative = 0. Then solve for the optimum diameter.

The reason you should do this for seven cans is that you get seven lids at a time, with minimum waste. Remember than seven cans require a total of 14 tops and bottoms

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