it took cindy 2h to bike from abbott to benson at a constant speed. the return trip took only 1.5h because she increased her speed by 6km/h. how far apart are abbott and benson?

distance = rate*time
a to b. d= r*2 hrs

b to a d=(r+6 km/hr)*1.5 hrs.
Set distances equal.
r*2=(r+6)*1.5 and solve for r which is the rate to travel in the 2 hours.
Distance = 2 hours x rate = ??
OR distance = 1.5 hours x (rate + 6 km/hr). I found r = 18 km/hr
so 18 km/hr x 2 hrs = 36 km.
OR (18+6) km/hr x 1.5 hours = 36 km.

Let L be the unknown separation distance. Let V be the speed for the frist trip.

L = (2 hours) * V
L = (1.5 hours) * (V + 6)

You have two equations in two unknowns and can sor both V and L.

2V = 1.5 V + 9
0.5 V = 18 V = 36 km/hr

Use that V to solve for L.

I made a mistake in the last equation of my previous answer. V = 18 km/hr
L = 18 x 2 = 36 km

To solve this problem, we can use the formula for distance: distance = rate * time.

Let's denote the distance between Abbott and Benson as L.

In the first trip from Abbott to Benson, Cindy took 2 hours to cover the distance L at a constant speed. Therefore, the equation becomes: L = r * 2, where r is the rate of speed.

In the return trip, Cindy increased her speed by 6 km/h and took only 1.5 hours. So the equation becomes: L = (r + 6) * 1.5.

Now, we can set these two equations equal to each other and solve for r:

r * 2 = (r + 6) * 1.5

Expanding this equation, we get:

2r = 1.5r + 9

Now, we can solve for r:

0.5r = 9

r = 18 km/h

Now that we know the rate of speed, we can find the distance between Abbott and Benson:

Distance = rate * time
Distance = 18 km/h * 2 hours
Distance = 36 km

So, Abbott and Benson are 36 km apart.