# math

posted by
**jennifer**
.

at 8:00am the smiths left a campground, driving at 48 mi/h. at 8:20am the garcias left the same camp ground and followed the same route, driving at 60 mi/h. at what time did they overtake the smith's?

How far did the Smiths drive from 8 a.m. to 8:20 a.m.; i.e., in 20 minutes?

distance = rate*time.

d = 48mi/hr * 1/3 hr = 16 miles which the Smiths had as a head start.

let x = distance driven by Garcias. time = d/r = x/60.

time for Smiths = x-16 is distance driven. time = (x-16)/48.

Set time = time or

x/60 = (x-16)/48

solve for x.

That will be the distance. Plug that into x/60=time and calculate time. Add that to 8:20 to know the final time at which both reached the same point. Post you work if you run into trouble.