Math
posted by K .
Find X
27^4x2=243^3x+6
Please explain how to do it.
Thanks
27^(4x2)=243^(3x+6)
Notice that 27 and 243 are both multiples of 3
Changing them..
(3^4)^(4x2)=(3^6)^(3x+6)
3^4(4x2)= 3^6(3x+6)
taking the log base 3 of each side.
(4x2)= (3x+6)
and solve for x.
That doesn't work if you check it, did you do it wrong?
oops.
27^(4x2)=243^(3x+6)
Notice that 27 and 243 are both multiples of 3
Changing them..
(3^4)^(4x2)=(3^6)^(3x+6)
3^4(4x2)= 3^6(3x+6)
taking the log base 3 of each side.
4(4x2)= 6(3x+6)
and solve for x.

27^4x2=243^3x+6 3^3(4x2)=3^5(3x+6) 3(4x2)=5(3x+6) 12x6=15x+30 12x15x=30+6 3x=36 x=36/3 x=12