Sunday

December 21, 2014

December 21, 2014

Posted by **tina** on Tuesday, November 28, 2006 at 11:40am.

If Joe runs at 6 mi/hr for 30 minutes (7:00 to 7:30), his distance traveled is 6 mi/hr x 0.5 hr = 3 miles.

Ken starts at 7:10 and runs until 7:30 for a time of 20 minutes. For Ken to just catch up with Joe in 20 minutes, the rate - distance/time = 3 mi divided by 1/3 Hr =3 x 3/1 = 9 miles/hr. So to overtake Joe, Ken must run one step faster somewhere in the 3 miles.

**Answer this Question**

**Related Questions**

Alegbra (math) - At 7:00 am , Joe starts jogging at 6 mi/h. At 7:10 am. Ken ...

Math - Joe weighs 30 lbs less than twice ken's weight. If ken gains 10 pounds ...

math - joe left a campsite on a trip down the river in a canoe, traveling a 6 km...

Math - Joe weighs 30 lbs less than twice ken's weight. If ken gains 10 pounds ...

Math - Joe and Steve went to the store and Joe had seen this jacket that he had ...

physics - Joe pushes horizontally on a heavy box across a rough surface at ...

math - Jim and Joe were running together. Jim's average speed was 400 meters per...

physical science - Joe baked a cake for his mother's birthday. When he removed ...

math - I borrowed money from Joe. I spent 5.50 of it on lunch, and half of the ...

Grammar Verbs - Is this the correct present tense verb in this sentence? Then ...