Posted by Bri on Monday, November 27, 2006 at 6:17pm.
A box of Cheerios and a box of Wheaties are accelerated accross a horizontal force vector F applied to the Cheerios box. THe magnitude of the frictional force on the Cheerios box is 2 N and the magnitude of the frictional force on the Wheaties box is 4 N. If the magnitude of the vector focre is 12 N what is the magnitude of the force on the Wheaties box from the Cheerios box?
Can you clearify what I have to do?
You need to determine the acceleration first, since you cannot apply force equilibrium to any box.
Fnet = (M1 + M2) a
Fnet = 12  2  4 = 6 N accel;erates the two boxes together.
Solve for a and then apply
F = M1 a
to the Cheerios box alone, to solve for the force net F acting on the Cheerios box.
F = 12  F', where F' is the force applied by the Wheaties box in front of it.
F' is the force that they want you to compute

physics  Anonymous, Monday, October 31, 2016 at 6:25pm
8.8N
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