Posted by **Bri** on Monday, November 27, 2006 at 6:17pm.

A box of Cheerios and a box of Wheaties are accelerated accross a horizontal force vector F applied to the Cheerios box. THe magnitude of the frictional force on the Cheerios box is 2 N and the magnitude of the frictional force on the Wheaties box is 4 N. If the magnitude of the vector focre is 12 N what is the magnitude of the force on the Wheaties box from the Cheerios box?

Can you clearify what I have to do?

You need to determine the acceleration first, since you cannot apply force equilibrium to any box.

Fnet = (M1 + M2) a

Fnet = 12 - 2 - 4 = 6 N accel;erates the two boxes together.

Solve for a and then apply

F = M1 a

to the Cheerios box alone, to solve for the force net F acting on the Cheerios box.

F = 12 - F', where F' is the force applied by the Wheaties box in front of it.

F' is the force that they want you to compute

## Answer this Question

## Related Questions

- physics - In the figure below, a box of Cheerios (mass mC = 0.8 kg) and a box of...
- physics - In the figure below, a box of Cheerios (mass mC = 1.0 kg) and a box of...
- physics - In the figure here, a box of Cheerios (mass mC = 1.4 kg) and a box of ...
- Physics-forces - 1. a force of 250N is used to push a heavy box down the street...
- Physics - A 54 kg box is being pushed a distance of 7.0 m across the floor by a ...
- Physics - A delivery person pulls a 35 kg box across the floor. The applied ...
- physics - Two boxes (b1 = 23 kg and b2 = 57 kg) are being pushed across a ...
- Physics - ohh sorry, in my first question... A 15 kg box sits on a horizontal ...
- Physics - A box of mass m1 = 10.0 kg rests on a smooth, horizontal floor next to...
- Calculus Physics - A box and one force vector, F1 is shown. F1 = + 10 N. If the ...

More Related Questions