Posted by **Bri** on Monday, November 27, 2006 at 6:17pm.

A box of Cheerios and a box of Wheaties are accelerated accross a horizontal force vector F applied to the Cheerios box. THe magnitude of the frictional force on the Cheerios box is 2 N and the magnitude of the frictional force on the Wheaties box is 4 N. If the magnitude of the vector focre is 12 N what is the magnitude of the force on the Wheaties box from the Cheerios box?

Can you clearify what I have to do?

You need to determine the acceleration first, since you cannot apply force equilibrium to any box.

Fnet = (M1 + M2) a

Fnet = 12 - 2 - 4 = 6 N accel;erates the two boxes together.

Solve for a and then apply

F = M1 a

to the Cheerios box alone, to solve for the force net F acting on the Cheerios box.

F = 12 - F', where F' is the force applied by the Wheaties box in front of it.

F' is the force that they want you to compute

- physics -
**Anonymous**, Monday, October 31, 2016 at 6:25pm
8.8N

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