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March 30, 2015

March 30, 2015

Posted by **Dee** on Sunday, November 26, 2006 at 2:42pm.

I found this question to be quite difficult will you please clearify each part of the question for me? I couldn't figure out what to do.

For (a), compute the velocity change needed in m/s and divide it by three says (converted to seconds). That will be the required acceleration im m/s^2

(b) To convert the acceleration to g's divide by 9.8 m^2/s per g

(c) F = m a

(d) at a speed of 0.1 c, it takes the spacecraft 10 times as long is it would take light to travel the same distance.

- physics -
**Mew**, Monday, February 7, 2011 at 8:10pmHello, I know this is 3 years late but for people like me who just needed your hints, this basically means that for (a)

take .10(3x10^8)(m/s) and divide it by 3 days/24hrs/3600s and you will get your m/s^2

For (b), take what you got in (a) and divide it by 9.8m/s^2 to get the magnitude.

(c), Multiply (a) by the mass of the ship.

(d) the hint basically answered it..

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