Posted by **Harry** on Sunday, November 26, 2006 at 1:42pm.

A hydrate of strontium choloride contains 40.54% water. What is the formula of the hydrate ?

SrCl2*xH2O.

H2O = 40.54%

SrCl2 = 100 - 40.54 = 59.46%

Take 100 g sample. This gives us

59.46g SrCl2 and 40.54g H2O.

Convert to mols.

mols SrCl2 = 59.46/158.5 = 0.375

mols H2O = 40.54/18.02 = 2.25

So the formula is (SrCl

_{2})

_{0.375}*2.5 H

_{2}O

But we want whole numbers; therefore, divide the smaller number by itself to obtain 1 (0.375/0.375 = 1.00) and divide the other number by 0.375. That should give you the whole number ratio. Post your work if you get stuck.

Thank you for your help. Yes i got the answer 6H20

Thank you for your help

## Answer this Question

## Related Questions

- chemistry - strontium chloride can be obtained as the anhydrous salt, SrCl2, and...
- Chemistry - A 32.907-g sample of a hydrate of Au (CN)3 contains 5.406 g H2O What...
- chem - a 2.50g sample of hydrate of calcium sulfate losses 0.523g of water when ...
- Chemistry - I need help with this lab. Write the equation for the decomposition ...
- Chemistry :/ - Experiment 1 results: mass of crucible 88g mass of hydrate 93g ...
- chemistry - I need help with this lab. Write the equation for the decomposition...
- Chemistry - Experiment 1 results: mass of crucible 88g mass of hydrate 93g mass ...
- chemistry - A 2.50 g sample of a hydrate of calcium sulphate losses 0.523 g of ...
- chemistry - Cobalt(2) chloride is commonly obtained from chemical supply houses ...
- chemistry - A 2.500 gram sample of hydrate of calcium sulfate loses 0.532 grams ...