Posted by **agirl** on Sunday, November 26, 2006 at 12:31am.

Please can someone help me solve this problem?

2/x + 6/x-1 less than or = -5

8/x -1 <= -5 Now add 1 to each side

8/x <= -4 so x must be < 0

Multiply both sides by x (a negative number). This means you have to change the direction of the >

8 >= -4x

Divide both sides by 4

2 >= -x

Multiply both sides by -1

-2 <= x < 0

thanks so much but can you please post the solution in integral notation for me

2 6

___ + ____ < or = - 5

X X - 1

I'm also not sure how you got 8x-1 I didn't know I could just add the two numerators if the denominators were different

## Answer this Question

## Related Questions

- math inequalities please check - A landscape designer has to design a ...
- math inequalities please check - A landscape designer has to design a ...
- algebra--distributive - how would you do this prob. negative4-(5y+6) = negative ...
- algrebra 2 - it is called completing the square here is the equation 4x^2-4x+1=9...
- math - Suppose you need $2.40 in postage to mail a package to a friend. You have...
- math - can someone please help me? I am stuck on a problem it deals with ...
- math,help,algebra I - I need help can someone help me get unstuck and let me ...
- math--pre alg - not sure i did right 3(f+2)+9=13+5f 3f+6+9 = 13+5f +9 3F+15 = 12...
- Solving rational inequalities - problem #1 (1+x)/(2x+3)<1 algebraically ...
- Rational Inequality with Absolute Value - Here's a question I'm having trouble ...

More Related Questions