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November 27, 2014

November 27, 2014

Posted by **Dee** on Saturday, November 25, 2006 at 11:23pm.

What would be the equations I should use to solve the problems? I can't find them from my textbook. a) is expose to be 307 N at -22 degrees from the positive x axis. b) is 3.67 m/s^2 at -22 degrees from the postitive x axis.

(a) Two forces act on Tarzan as he leaves the edge of the cliff; the rope tension (at a 22 degree angle to vertical) and gravity (820 N down). They already tell you what the vine tension is, so you just have to "resolve" that into

760 N sin 22 = 284.7 N horizontal and

760 N cos 22 = 704.7 N vertical. The net downward force is

820 - 704.7 = 115.3 N and the net horizontal force is 284.7.

Take the resultant of those for the magnitude of the net force. The ratio of the two forces equals the tangent of the direction angle.

(b) Divide each of those forces by his mass (820 N/9.8 m/s^2 = 83.7 kg) to get the accelerations in the corresponding directions

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