Posted by **Tom** on Friday, November 24, 2006 at 9:06pm.

A Norman window has the shape of a semicircle atop a rectangle so that the diameter of the semicircle is equal to the width of the rectangle. What is the area of the largest possible Norman window with a perimeter of 45 feet?

so the perimeter is:

pi*r + 2r + 2h = 45.

h= (45 - PIr - 2r)/2

The area equals = (pi*r^2)/2 + 2rh

what do i do from here?

<<what do i do from here?>>

(1) Substitute your h(r) equation into the A (r,h) equation to express Area (A) in terms of r only.

(2) Then compute dA/dr and set it equal to zero.

(3) The solution will be the maximum-area value of r.

(4) Then substitute that r into the A(r) equation to get the maximum area.

## Answer This Question

## Related Questions

- calculus - A Norman window has the shape of a semicircle atop a rectangle so ...
- Calculus - A Norman window has the shape of a semicircle atop a rectangle so ...
- Calculus - A Norman window has the shape of a semicircle atop a rectangle so ...
- Calculus - A Norman window has the shape of a semicircle atop a rectangle so ...
- Calculus - A Norman window has the shape of a semicircle atop a rectangle so ...
- Calculus - A Norman window has the shape of a semicircle atop a rectangle so ...
- Calculus - A Norman window has the shape of a semicircle atop a rectangle so ...
- Math (: - My answer doesn't make sense. It's too big. A Norman window has the ...
- Calculus - A Norman window has the shape of a semicircle atop a rectangle so ...
- calculus - A Norman window has the shape of a semicircle atop a rectangle so ...

More Related Questions