Wednesday
April 23, 2014

Homework Help: Calc

Posted by Norris on Thursday, November 23, 2006 at 10:15pm.

A car traveling at 43 ft/sec decelerates at a constant 5 feet per second squared. How many feet does the car travel before coming to a complete stop?

i tried a few different equations, none of the worked.

43t - 5t^2 = 0
43 - 10t = 0
21.5t^2 - (5/3)t^3 = 0

maybe im not supposed to set it to zero? i dont know what to do

This looks like the "anti-derivative" question I answered earlier this evening.

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