Posted by **amy** on Wednesday, November 22, 2006 at 7:21am.

implicit differentation

1.y^3=4(x^2+y^2)

2.y^2-3x+2y=0

help please

You consider y to be a function of x, but you don't explicitely solve for it. Then you formally differentiate w.r.t. x using the chain rule:

y^3(x) = 4(x^2+y^2(x)) --->

3y^2dy/dx = 8x + 8y dy/dx

y^2-3x+2y=0 --->

2ydy/dx - 3+2dy/dx = 0

## Answer this Question

## Related Questions

- calculus high school - 7y^4+x^3y+x=4 using implicit differentation, how do i ...
- Math - Calculus Question. - hey can someone explain to me the relationship ...
- Calculus - I'm having problems with this one. Can't get the right answer. ...
- calculus - I have been asked to solve this two different ways. The first way is...
- calculus - Using the chain rule... how can i differentiate this? y=x(x-2)
- math - can some one please help me with the following questions as i dont ...
- Calculus - Differentiate using the chain rule: y=(x+(x+x^(1/2))^(1/2))^(1/2) y...
- calculus - Thank you Reiny for replying.I know names have changed. Perhaps I ...
- calculus - Using 4x^2 - 9y^2 = 36 Find y by implicit differentiation and then ...
- Calculus - Using 4x^2 - 9y^2 = 36 Find y by implicit differentiation and then ...

More Related Questions