Friday

August 29, 2014

August 29, 2014

Posted by **Benji** on Monday, November 20, 2006 at 4:44pm.

I first drew the picture. How would I find the equation since F=ma doesn't include everything?

F=ma (combined with Newton's third law) give you all you need to solve this problem.

The force on the hanging mass in the downward direction is:

F2 = m2 * g - T

where m2 = 30 kg

The force on the other mass in the direction parallel to the plane in which the string is pulling is:

F1 = -m1 * g sin(40°) + T

where m1 = 20 kg

Begause the string is assumed to be of fixed length the acceleration of mass 1 in the direction the string is pulling must be the same as the acceleration of mass 2 in the downward direction.

This means that:

F1/m1 = F2/m2

**Related Questions**

physics - A mass of 20 kg on a plane inclined at 40 degrees. A string attached ...

physics - A mass of 20 kg on a plane inclined at 40 degrees. A string attached ...

physics - On an incline plane (raised to 30 degrees) is a block A which has a ...

Physics - A block P of mass 2.75 kg is lying on a rough inclined plane of angle...

physics - Two blocks are connected by a string over a frictionless, massless ...

Phsycis/Math (please help) - Two blocks are connected by a string over a ...

Physics - An inclined plane is on a table 1.4m tall. A 6kg box is hanging ...

Physics - A mass of m1 = 6.00 kg is sitting on an inclined plane, which meets ...

PHYSICS - A wheel in the shape of a uniform disk of radius R and mass mp is ...

Physics Classical Mechanics` - A wheel in the shape of a uniform disk of radius ...