Posted by **randy** on Monday, November 20, 2006 at 3:58pm.

A force of 30 N pulls a mass left at 30 degrees to the horizontal and one of 100 N pulls right at 120 degrees. If the mass of the mass which is 50 kg, find the acceletation if coeffcient of sliding is .01?

What would be the equation of this problem?

If you are talking about a SINGLE mass of 50 kg pulled in opposite directions, determine the net horizontal force. That would be

Fx = -100 cos 120 - 30 -Ff

where Ff is the friction force, whicb is (100 sin 120)* 0.1

I get

Fx = 50 - 30 - 8.67

for the net horizontal force. Divide by the mass to get acceleration.

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