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December 21, 2014

December 21, 2014

Posted by **Sara** on Friday, November 17, 2006 at 7:25pm.

heat lost + heat gained = 0

mcdeltaT + mcdeltaT = 0

substitute Tf - Ti for delta T (in both cases). Tf is final T and Ti is initial T. Solve for Tf. Post your work if you get stuck.

Jena: Please dont change names on us. We try to get to know what kind of errors each student is making in order to effectively instruct. Changing names messes that up.

Thanks.

The sum of the heat gains is zero (one will gain heat, the other lose (negative gain)).

0=heatwatermelon gained + heatsodagained

0=masswatermellon*c*(Tf-25) + 12*.35*csoda*(Tf-3.05)

solve for Tf.

(.35)(3800)(Tf-3.05)+(7.15)(4186)(Tf-25)=0

OK but how do I get the Tf for both in the same time

I am Jena's sister

Sorry if I made an error.bobpursley

You haven't multiplied 0.35 kg/can x 12 cans = ?? kg soda.

Just do algebra and the Tf will be the only unknown in the equation.

I am stuck I got a whole different #.

12*0.35*3800*(Tf-3.05) + 7.15*4186*(Tf-25.0)=0

15960Tf - 48678 + 29929.9Tf - 748247.5 = 0

Solve for Tf. I assume you can take it from here.

- Physics -
**Thomas**, Saturday, March 20, 2010 at 2:45pmTo solve for Tf, use algebra to slove for unknowns.

Try this:

(12)(0.35)(3800)(5)+(7.15)(4186)(25)/(12)(0.35)(3800)+(7.5)(4186)

and what's left over is the answer for your unknown

- Physics -
**Thomas**, Saturday, March 20, 2010 at 2:48pmI input the wrong temp of the soda can so just replace the (5) with (3.05) nd that will work

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